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To find the product of two numbers greater than five and less than ten, with finger math, make fist with the digits of your hands and correspondingly push the beads on the pythabacus against the left post. To efficiently do finger math students will need to know the 2, 3, 4 and 5's tables by heart. Students should practice the arithmetic waltz to become proficient at these tables.
On one hand extend digits one at a time while counting after the top number of the problem until you reach ten and on the other hand likewise for the bottom number of the problem. Write the number of digits extended on each hand beside the respective numerals, about half sized, with a times sign between them. On the pythabacus push a number of beads equal the digits on one hand against the right post, then push a number of beads equal the digits of the other hand midway toward the right post.
Now multiply the number equal the digits on one hand times the number equal the digits on the other hand and write the product directly under the factors. Pushing the triangle of beads previously pushed midway toward the right post back to the left should leave a quadrilateral composed of a number of beads equal this product.
Now count the combined number of  digits not extended on both hands and write this number to the left of the numeral under the factors. The number of digits not extended will equal the number of beads on the bottom row of the arrangement of beads against the left post of the pythabacus.  The problem is now solved!

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To find the product of two numbers greater than five and less than ten, with finger math, that involve carrying make fist, as before, with the digits of your hands and correspondingly push the beads on the pythabacus against the left post.
On one hand extend digits one at a time while counting after the top number of the problem until you reach ten and on the other hand likewise for the bottom number of the problem. Write the number of digits extended on each hand beside the respective numerals, about half sized, with a times sign between them. On the pythabacus push a number of beads equal the digits on one hand against the right post, then push a number of beads equal the digits of the other hand midway toward the right post.
Now multiply the number equal the digits on one hand times the number equal the digits on the other hand and write the product directly under the factors. Write the numeral representing the tens to be carried half sized to the left of the numeral representing the ones. Pushing the triangle of beads previously pushed midway toward the right post back to the left should leave a quadrilateral composed of a number of beads equal this product.
Now count the combined number of  digits not extended on both hands, and add to this number the number of carried tens. Write this number to the left of the numerals under the factors. The number of digits not extended, as before, will equal the number of beads on the bottom row of the arrangement of beads against the left post of the pythabacus.  The problem is now solved!
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